/* Program to Find Whether a Number is Palindrome or Not without
using String Functions */
main()
{
int n, reverse = 0, temp;
printf("Enter a number to check if it is a palindrome or not\n");
scanf("%d",&n);
temp = n;
while( temp != 0 )
{
reverse = reverse * 10;
reverse = reverse + temp%10;
temp = temp/10;
}
if ( n == reverse )
printf("%d is a palindrome number.\n", n);
else
printf("%d is not a palindrome number.\n", n);
return 0;
}
/* Program to Find Whether a String is Palindrome or Not without
using String Functions */
#include
#include
main()
{
char s1[20];
int i, j, len=0, flag=0;
printf("\nEnter any string: ");
gets(s1);
for (i=0; s1[i]!='\0'; i++)
len++;
i = 0;
j = len-1;
while (i < len)
{
if (s1[i] != s1[j])
{
flag = 1;
break;
}
i++;
j--;
}
if (flag == 0)
printf("\nString is palindrome");
else
printf("\nString is not palindrome");
getch();
}
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Wednesday, April 11, 2012
PALINDROME IN C WITHOUT USING STRING FUNCTION
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ReplyDelete//Single program for Both String or Integer to check palindrome
ReplyDelete//In java with out using string functions like reverse and equals method also and display matching characters also
package com.practice;
import java.util.Scanner;
public class Pallindrome {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
int i=0,j=0,k,count=0;
String input,temp;
System.out.println("Enter the String or Integer");
input=sc.nextLine();
temp=input;
k=temp.length()-1;
for(i=0;i<=input.length()-1;i++) {
if(input.charAt(j)==temp.charAt(k)) {
count++;
}
//For matching characters
j++;
k--;
}
System.out.println("Matching Characters = "+count);
if(count==input.length()) {
System.out.println("It's a pallindrome");
}
else {
System.out.println("It's not a pallindrome");
}
}
}
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Please suggest another method ....what if we use null character as every string terminated with null character
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